Allegiant Air G49300 Flight Status Today

Domestic flight Allegiant Air G49300 takes off from Cedar Rapids (CID) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves The Eastern Iowa Airport at 12:20 America/Chicago. The flight is expected to land at St. Petersburg-Clearwater International Airport at 15:30 America/New_York. The flight will last about 2 hours 10 minutes.

G49300 - AAY9300 Allegiant Air (G4)
CID Cedar Rapids United States
Flight CID to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure The Eastern Iowa Airport
IATA: CIDICAO: KCID
Scheduled 12:20
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 15:30
None 13
G49300 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 10 minutes
  • Flight Distance: 1753 kms / 1089 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KUZA1
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Cedar Rapids: Sunday 2026-04-05 18:23 PM
  • Current Time in Saint Petersburg: Sunday 2026-04-05 19:23 PM

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Allegiant Air Flight G49300 FAQs

What is the scheduled flight duration for Allegiant Air G49300 flight?

On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 1753 km (1089 miles).

What type of aircraft is used for the Allegiant Air G49300 flight?

All Allegiant Air G49300 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G49300 flights are operated a week?

1 flights per week. The Flight Allegiant Air G49300 is operated on Monday.