Allegiant Air G49108 Flight Status Today

Domestic flight Allegiant Air G49108 takes off from Fort Lauderdale (FLL) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Fort Lauderdale-Hollywood International Airport at 15:59 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 16:46 America/New_York. The flight will last about 46 minutes.

G49108 - AAY9108 Allegiant Air (G4)
FLL Fort Lauderdale United States
Flight FLL to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-April-2022
Departure Fort Lauderdale-Hollywood International Airport
IATA: FLLICAO: KFLL
Scheduled 15:59
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 16:46
None 12
G49108 Detail
  • Type: Domestic Flight
  • Flight Duration: 46 minutes
  • Flight Distance: 325 kms / 202 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Fort Lauderdale: Monday 2026-01-19 13:07 PM
  • Current Time in Saint Petersburg: Monday 2026-01-19 13:07 PM

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Allegiant Air Flight G49108 FAQs

What is the scheduled flight duration for Allegiant Air G49108 flight?

On average, nonstop flight takes 46 minutes, with the flight distance of 325 km (202 miles).

What type of aircraft is used for the Allegiant Air G49108 flight?

All Allegiant Air G49108 flights are operated using Airbus A320 aircraft.