Allegiant Air G46908 Flight Status from Oklahoma City to Fort Walton Beach, United States today

Domestic flight Allegiant Air G46908 from Oklahoma City (OKC) United States to Fort Walton Beach (VPS) United States operated by Allegiant Air. Scheduled time of departure from Will Rogers World Airport is 14:25 America/Chicago and scheduled time of arrival in Destin Fort Walton Beach Airport is None America/Chicago. The duration of the flight is 1 hours 36 minutes.

G46908 - AAY6908 Allegiant Air (G4)
OKC Oklahoma City United States
Flight OKC to VPS
VPS Fort Walton Beach United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 14:25
None None
Arrival Destin Fort Walton Beach Airport
IATA: VPSICAO: KVPS
Scheduled None
None None
G46908 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 1166 kms / 725 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320-214
  • Callsign: AAY6908
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Oklahoma City: Tuesday 2024-04-30 21:58 PM
  • Current Time in Fort Walton Beach: Tuesday 2024-04-30 21:58 PM

Similar flight route from Oklahoma City (OKC) to Fort Walton Beach (VPS)

Airline Flight no Departure Arrival
Allegiant Air G43104
Allegiant Air 		30/04/2024
19:15 (-6:00) 		1 hours 54 minutes
21:14 (-6:00)

Frequently asked questions, answered

How long is the flight from Oklahoma City to Fort Walton Beach?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 1166 km (725 miles).

What type of aircraft is used for the Allegiant Air G46908 flight?

All Allegiant Air G46908 flights are operated using Airbus A320-214 aircraft.