Allegiant Air G46245 Flight Status Today

Domestic flight Allegiant Air G46245 takes off from Asheville (AVL) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Asheville Regional Airport at 19:45 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 21:19 America/New_York. The flight will last about 1 hours 34 minutes.

G46245 - AAY6245 Allegiant Air (G4)
AVL Asheville United States
Flight AVL to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 13-June-2021
Departure Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 19:45
None 6
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 21:19
None 10
G46245 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: AAY6245
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Asheville: Tuesday 2026-01-20 09:54 AM
  • Current Time in Saint Petersburg: Tuesday 2026-01-20 09:54 AM

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Allegiant Air Flight G46245 FAQs

What is the scheduled flight duration for Allegiant Air G46245 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G46245 flight?

All Allegiant Air G46245 flights are operated using Airbus A320 aircraft.