Allegiant Air G46219 Flight Status Today

Domestic flight Allegiant Air G46219 takes off from Asheville (AVL) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Asheville Regional Airport at 12:30 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 14:04 America/New_York. The flight will last about 1 hours 25 minutes.

G46219 - AAY6219 Allegiant Air (G4)
AVL Asheville United States
Flight AVL to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-June-2021
Departure Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 12:30
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 14:04
None None
G46219 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 25 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Asheville: Sunday 2026-03-22 23:15 PM
  • Current Time in Saint Petersburg: Sunday 2026-03-22 23:15 PM

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Allegiant Air Flight G46219 FAQs

What is the scheduled flight duration for Allegiant Air G46219 flight?

On average, nonstop flight takes 1 hour(s) 25 minutes, with the flight distance of 834 km (518 miles).