Allegiant Air G46138 Flight Status Today

Domestic flight Allegiant Air G46138 takes off from Saint Petersburg (PIE) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 07:30 America/New_York. The flight is expected to land at McGhee Tyson Airport at 09:03 America/New_York. The flight will last about 1 hours 26 minutes.

G46138 - AAY6138 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 12-October-2021
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 07:30
None None
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 09:03
None None
G46138 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 26 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Thursday 2026-01-01 01:46 AM
  • Current Time in Knoxville: Thursday 2026-01-01 01:46 AM

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Allegiant Air Flight G46138 FAQs

What is the scheduled flight duration for Allegiant Air G46138 flight?

On average, nonstop flight takes 1 hour(s) 26 minutes, with the flight distance of 884 km (549 miles).