Allegiant Air G4610 Flight Status Today

Domestic flight Allegiant Air G4610 takes off from Saint Petersburg (PIE) United States to Indianapolis (IND) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 11:17 America/New_York. The flight is expected to land at Indianapolis International Airport at 13:41 America/Indiana/Indianapolis. The flight will last about 2 hours 24 minutes.

G4610 - AAY610 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to IND
IND Indianapolis United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 11:17
None 10
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 13:41
None B3
G4610 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 24 minutes
  • Flight Distance: 1351 kms / 839 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in Saint Petersburg: Wednesday 2026-02-11 12:23 PM
  • Current Time in Indianapolis: Wednesday 2026-02-11 12:23 PM

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Allegiant Air Flight G4610 FAQs

What is the scheduled flight duration for Allegiant Air G4610 flight?

On average, nonstop flight takes 2 hour(s) 24 minutes, with the flight distance of 1351 km (839 miles).

What type of aircraft is used for the Allegiant Air G4610 flight?

All Allegiant Air G4610 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G4610 flights are operated a week?

1 flights per week. The Flight Allegiant Air G4610 is operated on Saturday.