Allegiant Air G4608 Flight Status Today

Domestic flight Allegiant Air G4608 takes off from Jacksonville (JAX) United States to Indianapolis (IND) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 21:33 America/New_York. The flight is expected to land at Indianapolis International Airport at 23:34 America/Indiana/Indianapolis. The flight will last about 2 hours 1 minutes.

G4608 - AAY608 Allegiant Air (G4)
JAX Jacksonville United States
Flight JAX to IND
IND Indianapolis United States
Contact Airlines It may not operate on the date requested
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 21:33
None C6
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 23:34
None B3
G4608 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 1 minutes
  • Flight Distance: 1106 kms / 687 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Thursday, Friday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KCSV2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in Jacksonville: Sunday 2026-03-22 04:25 AM
  • Current Time in Indianapolis: Sunday 2026-03-22 04:25 AM

Flight routes similar to Allegiant Air G4608

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21:32 		2 hours 1 minutes
23:33

Allegiant Air Flight G4608 FAQs

What is the scheduled flight duration for Allegiant Air G4608 flight?

On average, nonstop flight takes 2 hour(s) 1 minutes, with the flight distance of 1106 km (687 miles).

What type of aircraft is used for the Allegiant Air G4608 flight?

All Allegiant Air G4608 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G4608 flights are operated a week?

4 flights per week. The Flight Allegiant Air G4608 is operated on Monday, Thursday, Friday, Sunday.