Allegiant Air G45797 Flight Status from Cleveland to Saint Petersburg, United States today

Domestic flight Allegiant Air G45797 from Cleveland (CLE) United States to Saint Petersburg (PIE) United States operated by Allegiant Air. Scheduled time of departure from Cleveland Hopkins International Airport is 13:26 America/New_York and scheduled time of arrival in St. Petersburg-Clearwater International Airport is 15:45 America/New_York. The duration of the flight is 2 hours 14 minutes.

G45797 - AAY5797 Allegiant Air (G4)
CLE Cleveland United States
Flight CLE to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 20-July-2021
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 13:26
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 15:45
None None
G45797 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 14 minutes
  • Flight Distance: 1500 kms / 932 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2024-04-29 07:27 AM
  • Current Time in Saint Petersburg: Monday 2024-04-29 07:27 AM

Frequently asked questions, answered

How long is the flight from Cleveland to Saint Petersburg?

On average, nonstop flight takes 2 hour(s) 14 minutes, with the flight distance of 1500 km (932 miles).

What type of aircraft is used for the Allegiant Air G45797 flight?

All Allegiant Air G45797 flights are operated using Airbus A320 aircraft.