Allegiant Air G45769 Flight Status Today

Domestic flight Allegiant Air G45769 takes off from Saint Petersburg (PIE) United States to Bloomington (BMI) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 13:15 America/New_York. The flight is expected to land at Central Illinois Regional Airport at 14:36 America/Chicago. The flight will last about 2 hours 9 minutes.

G45769 - AAY5769 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to BMI
BMI Bloomington United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-August-2021
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 13:15
None None
Arrival Central Illinois Regional Airport
IATA: BMIICAO: KBMI
Scheduled 14:36
None None
G45769 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 9 minutes
  • Flight Distance: 1507 kms / 936 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Saint Petersburg: Wednesday 2025-12-31 23:44 PM
  • Current Time in Bloomington: Wednesday 2025-12-31 22:44 PM

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Allegiant Air Flight G45769 FAQs

What is the scheduled flight duration for Allegiant Air G45769 flight?

On average, nonstop flight takes 2 hour(s) 9 minutes, with the flight distance of 1507 km (936 miles).