Allegiant Air G44986 Flight Status Today

Domestic flight Allegiant Air G44986 takes off from Saint Petersburg (PIE) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 13:52 America/New_York. The flight is expected to land at McGhee Tyson Airport at 15:26 America/New_York. The flight will last about 1 hours 34 minutes.

G44986 - AAY4986 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 13:52
None 3
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 15:26
None 2
G44986 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A320
  • Callsign: AAY986
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Wednesday 2025-12-31 11:12 AM
  • Current Time in Knoxville: Wednesday 2025-12-31 11:12 AM

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Allegiant Air Flight G44986 FAQs

What is the scheduled flight duration for Allegiant Air G44986 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 884 km (549 miles).

What type of aircraft is used for the Allegiant Air G44986 flight?

All Allegiant Air G44986 flights are operated using Airbus A320 aircraft.