Allegiant Air G44925 Flight Status Today

Domestic flight Allegiant Air G44925 takes off from Cleveland (CLE) United States to Austin (AUS) United States. It's operated by Allegiant Air. The plane leaves Cleveland Hopkins International Airport at 10:13 America/New_York. The flight is expected to land at Austin-Bergstrom International Airport at 12:17 America/Chicago. The flight will last about 3 hours 7 minutes.

G44925 - AAY4925 Allegiant Air (G4)
CLE Cleveland United States
Flight CLE to AUS
AUS Austin United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 10:13
Arrival Austin-Bergstrom International Airport
IATA: AUSICAO: KAUS
Scheduled 12:17
G44925 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 7 minutes
  • Flight Distance: 1890 kms / 1174 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A319
  • Callsign: AAY925
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Cleveland: Monday 2026-01-19 14:12 PM
  • Current Time in Austin: Monday 2026-01-19 13:12 PM

Flight routes similar to Allegiant Air G44925

Airline Flight no Departure Arrival
Frontier Airlines F94001
Frontier Airlines 		19/01/2026
15:55 		3 hours 20 minutes
18:15

Allegiant Air Flight G44925 FAQs

What is the scheduled flight duration for Allegiant Air G44925 flight?

On average, nonstop flight takes 3 hour(s) 7 minutes, with the flight distance of 1890 km (1174 miles).

What type of aircraft is used for the Allegiant Air G44925 flight?

All Allegiant Air G44925 flights are operated using Airbus A319 aircraft.