Allegiant Air G44914 Flight Status Today

Domestic flight Allegiant Air G44914 takes off from Saint Petersburg (PIE) United States to Greenville (GSP) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 12:00 America/New_York. The flight is expected to land at Greenville-Spartanburg International Airport at 13:20 America/New_York. The flight will last about 2 hours 6 minutes.

G44914 - AAY4914 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to GSP
GSP Greenville United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 12:00
None None
Arrival Greenville-Spartanburg International Airport
IATA: GSPICAO: KGSP
Scheduled 13:20
None None
G44914 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 6 minutes
  • Flight Distance: 775 kms / 482 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A320
  • Callsign: AAY914
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Sunday 2026-03-01 22:49 PM
  • Current Time in Greenville: Sunday 2026-03-01 22:49 PM

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Allegiant Air Flight G44914 FAQs

What is the scheduled flight duration for Allegiant Air G44914 flight?

On average, nonstop flight takes 2 hour(s) 6 minutes, with the flight distance of 775 km (482 miles).

What type of aircraft is used for the Allegiant Air G44914 flight?

All Allegiant Air G44914 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G44914 flights are operated a week?

1 flights per week. The Flight Allegiant Air G44914 is operated on Sunday.