Allegiant Air G44893 Flight Status Today

Domestic flight Allegiant Air G44893 takes off from Saint Petersburg (PIE) United States to Huntington (HTS) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 11:35 America/New_York. The flight is expected to land at Tri-State/Milton Airport at 13:31 America/New_York. The flight will last about 4 hours 17 minutes.

G44893 - AAY4893 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to HTS
HTS Huntington United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 11:35
None 4
Arrival Tri-State/Milton Airport
IATA: HTSICAO: KHTS
Scheduled 13:31
None 01
G44893 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 17 minutes
  • Flight Distance: 1160 kms / 721 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-CYTR2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Thursday 2026-01-01 05:00 AM
  • Current Time in Huntington: Thursday 2026-01-01 05:00 AM

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Allegiant Air Flight G44893 FAQs

What is the scheduled flight duration for Allegiant Air G44893 flight?

On average, nonstop flight takes 4 hour(s) 17 minutes, with the flight distance of 1160 km (721 miles).

What type of aircraft is used for the Allegiant Air G44893 flight?

All Allegiant Air G44893 flights are operated using Airbus A320 aircraft.