Allegiant Air G44838 Flight Status Today

Domestic flight Allegiant Air G44838 takes off from Norfolk (ORF) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Norfolk International Airport at 21:34 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 23:32 America/New_York. The flight will last about 1 hours 58 minutes.

G44838 - AAY4838 Allegiant Air (G4)
ORF Norfolk United States
Flight ORF to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Norfolk International Airport
IATA: ORFICAO: KORF
Scheduled 21:34
None B17
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 23:32
None 12
G44838 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 58 minutes
  • Flight Distance: 1168 kms / 726 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A320
  • Callsign: AAY838
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Norfolk: Saturday 2026-03-21 00:03 AM
  • Current Time in Saint Petersburg: Saturday 2026-03-21 00:03 AM

Allegiant Air Flight G44838 FAQs

What is the scheduled flight duration for Allegiant Air G44838 flight?

On average, nonstop flight takes 1 hour(s) 58 minutes, with the flight distance of 1168 km (726 miles).

What type of aircraft is used for the Allegiant Air G44838 flight?

All Allegiant Air G44838 flights are operated using Airbus A320 aircraft.