Allegiant Air G44447 Flight Status Today

Domestic flight Allegiant Air G44447 takes off from Orlando (SFB) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Orlando Sanford International Airport at 16:18 America/New_York. The flight is expected to land at McGhee Tyson Airport at 17:51 America/New_York. The flight will last about 1 hours 33 minutes.

G44447 - AAY4447 Allegiant Air (G4)
SFB Orlando United States
Flight SFB to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Orlando Sanford International Airport
IATA: SFBICAO: KSFB
Scheduled 16:18
B 15
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 17:51
None None
G44447 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 33 minutes
  • Flight Distance: 821 kms / 510 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 156
  • Freight capacity: 6.7 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A320
  • Callsign: AAY447
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Orlando: Monday 2026-01-19 08:52 AM
  • Current Time in Knoxville: Monday 2026-01-19 08:52 AM

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Allegiant Air Flight G44447 FAQs

What is the scheduled flight duration for Allegiant Air G44447 flight?

On average, nonstop flight takes 1 hour(s) 33 minutes, with the flight distance of 821 km (510 miles).

What type of aircraft is used for the Allegiant Air G44447 flight?

All Allegiant Air G44447 flights are operated using Airbus A320 aircraft.