Allegiant Air G43795 flight status now

G43795 - AAY3795 Allegiant Air (G4)
JAX Jacksonville United States
Flight JAX to MDT
MDT Middletown United States
Contact Airlines It may not operate on the date requested
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 09:25
None C6
Arrival Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 11:30
None B6
G43795 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 58 minutes
  • Flight Distance: 1166 kms / 724 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Jacksonville: Thursday 2025-11-20 22:41 PM
  • Current Time in Middletown: Thursday 2025-11-20 22:41 PM

Domestic flight Allegiant Air G43795 takes off from Jacksonville (JAX) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves Jacksonville International Airport at 09:25 America/New_York. The flight is expected to land at Harrisburg International Airport at 11:30 America/New_York. The flight will last about 1 hours 58 minutes.

Frequently asked questions, answered

How long is the flight from Jacksonville to Middletown?

On average, nonstop flight takes 1 hour(s) 58 minutes, with the flight distance of 1166 km (724 miles).

What type of aircraft is used for the Allegiant Air G43795 flight?

All Allegiant Air G43795 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G43795 flights are operated a week?

1 flights per week. The Flight Allegiant Air G43795 is operated on Friday.