Allegiant Air G43735 Flight Status Today

Domestic flight Allegiant Air G43735 takes off from Bloomington (BMI) United States to Orlando (SFB) United States. It's operated by Allegiant Air. The plane leaves Central Illinois Regional Airport at 08:46 America/Chicago. The flight is expected to land at Orlando Sanford International Airport at 12:05 America/New_York. The flight will last about 2 hours 2 minutes.

G43735 - AAY3735 Allegiant Air (G4)
BMI Bloomington United States
Flight BMI to SFB
SFB Orlando United States
Contact Airlines It may not operate on the date requested
Departure Central Illinois Regional Airport
IATA: BMIICAO: KBMI
Scheduled 08:46
None None
Arrival Orlando Sanford International Airport
IATA: SFBICAO: KSFB
Scheduled 12:05
None None
G43735 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 2 minutes
  • Flight Distance: 1476 kms / 917 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Bloomington: Monday 2025-12-29 21:43 PM
  • Current Time in Orlando: Monday 2025-12-29 22:43 PM

Flight routes similar to Allegiant Air G43735

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Allegiant Air Flight G43735 FAQs

What is the scheduled flight duration for Allegiant Air G43735 flight?

On average, nonstop flight takes 2 hour(s) 2 minutes, with the flight distance of 1476 km (917 miles).

What type of aircraft is used for the Allegiant Air G43735 flight?

All Allegiant Air G43735 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G43735 flights are operated a week?

1 flights per week. The Flight Allegiant Air G43735 is operated on Tuesday.