Allegiant Air G43585 Flight Status Today

Domestic flight Allegiant Air G43585 takes off from Saint Petersburg (PIE) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 10:15 America/New_York. The flight is expected to land at McGhee Tyson Airport at 11:48 America/New_York. The flight will last about 1 hours 33 minutes.

G43585 - AAY3585 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-September-2021
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 10:15
None 7
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 11:48
None None
G43585 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 33 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Wednesday 2025-12-31 11:13 AM
  • Current Time in Knoxville: Wednesday 2025-12-31 11:13 AM

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Allegiant Air Flight G43585 FAQs

What is the scheduled flight duration for Allegiant Air G43585 flight?

On average, nonstop flight takes 1 hour(s) 33 minutes, with the flight distance of 884 km (549 miles).

What type of aircraft is used for the Allegiant Air G43585 flight?

All Allegiant Air G43585 flights are operated using Airbus A320 aircraft.