Allegiant Air G43048 Flight Status Today

Domestic flight Allegiant Air G43048 takes off from Knoxville (TYS) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 06:20 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 08:03 America/New_York. The flight will last about 1 hours 38 minutes.

G43048 - AAY3048 Allegiant Air (G4)
TYS Knoxville United States
Flight TYS to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 06:20
None 4
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 08:03
None 9
G43048 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 38 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KGNV3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Sunday 2026-04-12 02:32 AM
  • Current Time in Saint Petersburg: Sunday 2026-04-12 02:32 AM

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Allegiant Air Flight G43048 FAQs

What is the scheduled flight duration for Allegiant Air G43048 flight?

On average, nonstop flight takes 1 hour(s) 38 minutes, with the flight distance of 884 km (549 miles).

What type of aircraft is used for the Allegiant Air G43048 flight?

All Allegiant Air G43048 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G43048 flights are operated a week?

1 flights per week. The Flight Allegiant Air G43048 is operated on Thursday.