Allegiant Air G43030 Flight Status Today

Domestic flight Allegiant Air G43030 takes off from Knoxville (TYS) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 14:28 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 16:09 America/New_York. The flight will last about 1 hours 41 minutes.

G43030 - AAY3030 Allegiant Air (G4)
TYS Knoxville United States
Flight TYS to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 14:28
None 2
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 16:09
None 3
G43030 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 41 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Tuesday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KTYS1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Wednesday 2025-12-31 11:14 AM
  • Current Time in Saint Petersburg: Wednesday 2025-12-31 11:14 AM

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Allegiant Air Flight G43030 FAQs

What is the scheduled flight duration for Allegiant Air G43030 flight?

On average, nonstop flight takes 1 hour(s) 41 minutes, with the flight distance of 884 km (549 miles).

What type of aircraft is used for the Allegiant Air G43030 flight?

All Allegiant Air G43030 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G43030 flights are operated a week?

2 flights per week. The Flight Allegiant Air G43030 is operated on Tuesday, Saturday.