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Allegiant Air G42983 Flight Status Today
Domestic flight Allegiant Air G42983 takes off from Sarasota (SRQ) United States to Austin (AUS) United States. It's operated by Allegiant Air. The plane leaves Sarasota Bradenton International Airport at 14:10 America/New_York. The flight is expected to land at Austin-Bergstrom International Airport at 15:54 America/Chicago. The flight will last about 2 hours 44 minutes.
- Type: Domestic Flight
- Flight Duration: 2 hours 44 minutes
- Flight Distance: 1507 kms / 936 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Airbus A320
- Callsign: F-KSRQ2
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Sarasota: Monday 2026-01-19 02:01 AM
- Current Time in Austin: Monday 2026-01-19 01:01 AM
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Allegiant Air Flight G42983 FAQs
What is the scheduled flight duration for Allegiant Air G42983 flight?
On average, nonstop flight takes 2 hour(s) 44 minutes, with the flight distance of 1507 km (936 miles).
What type of aircraft is used for the Allegiant Air G42983 flight?
All Allegiant Air G42983 flights are operated using Airbus A320 aircraft.
Which terminal the flight Allegiant Air G42983 is arriving at?
Flight Allegiant Air G42983 arrives in Austin-Bergstrom International Airport at Terminal S.
How many Allegiant Air G42983 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42983 is operated on Thursday.
