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Allegiant Air G42980 Flight Status Today
Domestic flight Allegiant Air G42980 takes off from Sarasota (SRQ) United States to Fort Wayne (FWA) United States. It's operated by Allegiant Air. The plane leaves Sarasota Bradenton International Airport at 16:05 09 February 2026 America/New_York. The flight is expected to land at Fort Wayne International Airport at 18:44 09 February 2026 America/Indiana/Indianapolis. The flight will last about 2 hours 39 minutes.
Current status of G42980 is Scheduled On time Expected Depart in 5 hours, 29 minutes
G42980 - AAY2980
Allegiant Air (G4)
SRQ
Sarasota United States
FWA
Fort Wayne United States
Scheduled On time
Expected Depart in 5 hours, 29 minutes
Scheduled
16:05 09 February 2026
None
None
Scheduled
18:44 09 February 2026
None
7
G42980 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 39 minutes
- Flight Distance: 1528 kms / 949 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Wednesday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Airbus A320
- Callsign: F-KLEX5
- Departure Timezone: America/New_York
- Arrival Timezone: America/Indiana/Indianapolis
- Current Time in Sarasota: Monday 2026-02-09 10:36 AM
- Current Time in Fort Wayne: Monday 2026-02-09 10:36 AM
Allegiant Air Flight G42980 FAQs
What is the scheduled flight duration for Allegiant Air G42980 flight?
On average, nonstop flight takes 2 hour(s) 39 minutes, with the flight distance of 1528 km (949 miles).
What is the current status of Allegiant Air G42980 flight?
The current status of flight Allegiant Air G42980 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42980 flight?
All Allegiant Air G42980 flights are operated using Airbus A320 aircraft.
How many Allegiant Air G42980 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42980 is operated on Wednesday.