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Allegiant Air G42703 Flight Status Today
Domestic flight Allegiant Air G42703 takes off from Bloomington (BMI) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Central Illinois Regional Airport at 10:47 America/Chicago. The flight is expected to land at St. Petersburg-Clearwater International Airport at 14:07 America/New_York. The flight will last about 2 hours 13 minutes.
G42703 - AAY2703
Allegiant Air (G4)
BMI
Bloomington United States
PIE
Saint Petersburg United States
Contact Airlines
It may not operate on the date requested
G42703 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 13 minutes
- Flight Distance: 1507 kms / 936 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KTPA1
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Bloomington: Wednesday 2025-12-31 22:46 PM
- Current Time in Saint Petersburg: Wednesday 2025-12-31 23:46 PM
Flight routes similar to Allegiant Air G42703
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G42661 Allegiant Air |
31/12/2025 20:12 |
2 hours 19 minutes 23:31 |
Allegiant Air Flight G42703 FAQs
What is the scheduled flight duration for Allegiant Air G42703 flight?
On average, nonstop flight takes 2 hour(s) 13 minutes, with the flight distance of 1507 km (936 miles).
What type of aircraft is used for the Allegiant Air G42703 flight?
All Allegiant Air G42703 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G42703 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42703 is operated on Thursday.