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Allegiant Air G42688 Flight Status Today
Domestic flight Allegiant Air G42688 takes off from Saint Petersburg (PIE) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 21:05 01 March 2026 America/New_York. The flight is expected to land at Harrisburg International Airport at 23:07 01 March 2026 America/New_York. The flight will last about 2 hours 2 minutes.
Current status of G42688 is Scheduled On time Expected Depart in 11 hours, 11 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 2 minutes
- Flight Distance: 1468 kms / 912 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A319
- Callsign: F-KGNV2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Sunday 2026-03-01 09:54 AM
- Current Time in Middletown: Sunday 2026-03-01 09:54 AM
Allegiant Air Flight G42688 FAQs
What is the scheduled flight duration for Allegiant Air G42688 flight?
On average, nonstop flight takes 2 hour(s) 2 minutes, with the flight distance of 1468 km (912 miles).
What is the current status of Allegiant Air G42688 flight?
The current status of flight Allegiant Air G42688 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42688 flight?
All Allegiant Air G42688 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G42688 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42688 is operated on Thursday.
