Allegiant Air G42688 Flight Status Today

Domestic flight Allegiant Air G42688 takes off from Middletown (MDT) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 09:41 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 12:22 America/New_York. The flight will last about 2 hours 41 minutes.

G42688 - AAY2688 Allegiant Air (G4)
MDT Middletown United States
Flight MDT to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 09:41
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 12:22
None 9
G42688 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 41 minutes
  • Flight Distance: 1468 kms / 912 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KGNV2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Middletown: Monday 2025-12-29 06:28 AM
  • Current Time in Saint Petersburg: Monday 2025-12-29 06:28 AM

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Allegiant Air Flight G42688 FAQs

What is the scheduled flight duration for Allegiant Air G42688 flight?

On average, nonstop flight takes 2 hour(s) 41 minutes, with the flight distance of 1468 km (912 miles).

What type of aircraft is used for the Allegiant Air G42688 flight?

All Allegiant Air G42688 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G42688 flights are operated a week?

1 flights per week. The Flight Allegiant Air G42688 is operated on Thursday.