Allegiant Air G42688 Flight Status Today

Domestic flight Allegiant Air G42688 takes off from Saint Petersburg (PIE) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 06:50 America/New_York. The flight is expected to land at Harrisburg International Airport at 09:08 America/New_York. The flight will last about 2 hours 25 minutes.

G42688 - AAY2688 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to MDT
MDT Middletown United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 06:50
None 3
Arrival Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 09:08
None B6
G42688 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 25 minutes
  • Flight Distance: 1468 kms / 912 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KGNV2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-01-19 17:38 PM
  • Current Time in Middletown: Monday 2026-01-19 17:38 PM

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Allegiant Air Flight G42688 FAQs

What is the scheduled flight duration for Allegiant Air G42688 flight?

On average, nonstop flight takes 2 hour(s) 25 minutes, with the flight distance of 1468 km (912 miles).

What type of aircraft is used for the Allegiant Air G42688 flight?

All Allegiant Air G42688 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G42688 flights are operated a week?

1 flights per week. The Flight Allegiant Air G42688 is operated on Thursday.