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Allegiant Air G42608 flight status now
G42608 - AAY2608
Allegiant Air (G4)
LCK
Columbus United States
PIE
Saint Petersburg United States
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It may not operate on the date requested
G42608 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 9 minutes
- Flight Distance: 1321 kms / 821 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Wednesday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KSGF3
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Columbus: Tuesday 2025-11-18 14:00 PM
- Current Time in Saint Petersburg: Tuesday 2025-11-18 14:00 PM
Domestic flight Allegiant Air G42608 takes off from Columbus (LCK) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Rickenbacker International Airport at 12:10 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 14:24 America/New_York. The flight will last about 2 hours 9 minutes.
Frequently asked questions, answered
How long is the flight from Columbus to Saint Petersburg?
On average, nonstop flight takes 2 hour(s) 9 minutes, with the flight distance of 1321 km (821 miles).
What type of aircraft is used for the Allegiant Air G42608 flight?
All Allegiant Air G42608 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G42608 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42608 is operated on Wednesday.
