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Allegiant Air G42600 Flight Status Today
Domestic flight Allegiant Air G42600 takes off from Saint Petersburg (PIE) United States to Louisville (SDF) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 10:34 24 March 2026 America/New_York. The flight is expected to land at Louisville International Airport-Standiford Field at 13:17 24 March 2026 America/New_York. The flight will last about 2 hours 43 minutes.
Current status of G42600 is Scheduled On time Expected Depart in 4 hours, 51 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 43 minutes
- Flight Distance: 1173 kms / 729 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Friday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KCAE4
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Tuesday 2026-03-24 05:43 AM
- Current Time in Louisville: Tuesday 2026-03-24 05:43 AM
Flight routes similar to Allegiant Air G42600
Allegiant Air Flight G42600 FAQs
What is the scheduled flight duration for Allegiant Air G42600 flight?
On average, nonstop flight takes 2 hour(s) 43 minutes, with the flight distance of 1173 km (729 miles).
What is the current status of Allegiant Air G42600 flight?
The current status of flight Allegiant Air G42600 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G42600 flight?
All Allegiant Air G42600 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G42600 flights are operated a week?
1 flights per week. The Flight Allegiant Air G42600 is operated on Friday.
