Allegiant Air G42600 Flight Status Today

Domestic flight Allegiant Air G42600 takes off from Saint Petersburg (PIE) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 14:50 America/New_York. The flight is expected to land at Harrisburg International Airport at 17:14 America/New_York. The flight will last about 2 hours 24 minutes.

G42600 - AAY2600 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to MDT
MDT Middletown United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 14:50
None 3
Arrival Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 17:14
None None
G42600 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 24 minutes
  • Flight Distance: 1468 kms / 912 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KCAE4
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-01-19 13:55 PM
  • Current Time in Middletown: Monday 2026-01-19 13:55 PM

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None
19:30

Allegiant Air Flight G42600 FAQs

What is the scheduled flight duration for Allegiant Air G42600 flight?

On average, nonstop flight takes 2 hour(s) 24 minutes, with the flight distance of 1468 km (912 miles).

What type of aircraft is used for the Allegiant Air G42600 flight?

All Allegiant Air G42600 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G42600 flights are operated a week?

1 flights per week. The Flight Allegiant Air G42600 is operated on Friday.