Allegiant Air G42598 Flight Status Today

Domestic flight Allegiant Air G42598 takes off from Asheville (AVL) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Asheville Regional Airport at 10:27 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 12:04 America/New_York. The flight will last about 1 hours 41 minutes.

G42598 - AAY2598 Allegiant Air (G4)
AVL Asheville United States
Flight AVL to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 10:27
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 12:04
None 3
G42598 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 41 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Thursday, Friday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KBID1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Asheville: Thursday 2026-04-16 04:21 AM
  • Current Time in Saint Petersburg: Thursday 2026-04-16 04:21 AM

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Allegiant Air Flight G42598 FAQs

What is the scheduled flight duration for Allegiant Air G42598 flight?

On average, nonstop flight takes 1 hour(s) 41 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G42598 flight?

All Allegiant Air G42598 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G42598 flights are operated a week?

4 flights per week. The Flight Allegiant Air G42598 is operated on Monday, Thursday, Friday, Sunday.