Allegiant Air G4246 Flight Status Today

Domestic flight Allegiant Air G4246 takes off from Saint Petersburg (PIE) United States to Asheville (AVL) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 22:00 America/New_York. The flight is expected to land at Asheville Regional Airport at 23:36 America/New_York. The flight will last about 1 hours 36 minutes.

G4246 - AAY246 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to AVL
AVL Asheville United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 22:00
None 10
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 23:36
None None
G4246 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KINT1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-03-23 00:57 AM
  • Current Time in Asheville: Monday 2026-03-23 00:57 AM

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Allegiant Air Flight G4246 FAQs

What is the scheduled flight duration for Allegiant Air G4246 flight?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G4246 flight?

All Allegiant Air G4246 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G4246 flights are operated a week?

2 flights per week. The Flight Allegiant Air G4246 is operated on Monday, Friday.