Allegiant Air G42118 Flight Status Today

Domestic flight Allegiant Air G42118 takes off from Fort Lauderdale (FLL) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Fort Lauderdale-Hollywood International Airport at 12:10 America/New_York. The flight is expected to land at McGhee Tyson Airport at 14:14 America/New_York. The flight will last about 1 hours 54 minutes.

G42118 - AAY2118 Allegiant Air (G4)
FLL Fort Lauderdale United States
Flight FLL to TYS
TYS Knoxville United States
Contact Airlines It may not operate on the date requested
Departure Fort Lauderdale-Hollywood International Airport
IATA: FLLICAO: KFLL
Scheduled 12:10
1 C7
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 14:14
None 2
G42118 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 54 minutes
  • Flight Distance: 1140 kms / 708 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KHWO1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Fort Lauderdale: Wednesday 2025-12-31 03:04 AM
  • Current Time in Knoxville: Wednesday 2025-12-31 03:04 AM

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Allegiant Air Flight G42118 FAQs

What is the scheduled flight duration for Allegiant Air G42118 flight?

On average, nonstop flight takes 1 hour(s) 54 minutes, with the flight distance of 1140 km (708 miles).

What type of aircraft is used for the Allegiant Air G42118 flight?

All Allegiant Air G42118 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G42118 flights are operated a week?

1 flights per week. The Flight Allegiant Air G42118 is operated on Friday.