Allegiant Air G41906 Flight Status Today

Domestic flight Allegiant Air G41906 takes off from Norfolk (ORF) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Norfolk International Airport at 21:17 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 23:17 America/New_York. The flight will last about 2 hours 4 minutes.

G41906 - AAY1906 Allegiant Air (G4)
ORF Norfolk United States
Flight ORF to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 13-April-2022
Departure Norfolk International Airport
IATA: ORFICAO: KORF
Scheduled 21:17
None B20
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 23:17
None None
G41906 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 4 minutes
  • Flight Distance: 1168 kms / 726 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Norfolk: Friday 2026-03-20 20:20 PM
  • Current Time in Saint Petersburg: Friday 2026-03-20 20:20 PM

Allegiant Air Flight G41906 FAQs

What is the scheduled flight duration for Allegiant Air G41906 flight?

On average, nonstop flight takes 2 hour(s) 4 minutes, with the flight distance of 1168 km (726 miles).

What type of aircraft is used for the Allegiant Air G41906 flight?

All Allegiant Air G41906 flights are operated using Airbus A319 aircraft.