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Allegiant Air G41488 Flight Status Today
Domestic flight Allegiant Air G41488 takes off from Fort Walton Beach (VPS) United States to Akron (CAK) United States. It's operated by Allegiant Air. The plane leaves Destin Fort Walton Beach Airport at 12:09 13 April 2026 America/Chicago. The flight is expected to land at Akron-Canton Airport at 15:23 13 April 2026 America/New_York. The flight will last about 2 hours 11 minutes.
Current status of G41488 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 2 hours 11 minutes
- Flight Distance: 1245 kms / 773 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Friday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A319
- Callsign: F-KECP1
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Fort Walton Beach: Monday 2026-04-13 14:29 PM
- Current Time in Akron: Monday 2026-04-13 15:29 PM
Flight routes similar to Allegiant Air G41488
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43074 Allegiant Air |
13/04/2026 12:11 |
1 hours 58 minutes 15:25 |
Allegiant Air Flight G41488 FAQs
What is the scheduled flight duration for Allegiant Air G41488 flight?
On average, nonstop flight takes 2 hour(s) 11 minutes, with the flight distance of 1245 km (773 miles).
What is the current status of Allegiant Air G41488 flight?
The current status of flight Allegiant Air G41488 is Arrived On time.
What type of aircraft is used for the Allegiant Air G41488 flight?
All Allegiant Air G41488 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41488 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41488 is operated on Friday.
