Allegiant Air G41470 flight status now

G41470 - AAY1470 Allegiant Air (G4)
VPS Fort Walton Beach United States
Flight VPS to OKC
OKC Oklahoma City United States
Contact Airlines It may not operate on the date requested
Departure Destin Fort Walton Beach Airport
IATA: VPSICAO: KVPS
Scheduled 17:15
None None
Arrival Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 19:27
None None
G41470 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 3 minutes
  • Flight Distance: 1166 kms / 725 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KSGT1
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Fort Walton Beach: Thursday 2025-11-20 02:38 AM
  • Current Time in Oklahoma City: Thursday 2025-11-20 02:38 AM

Domestic flight Allegiant Air G41470 takes off from Fort Walton Beach (VPS) United States to Oklahoma City (OKC) United States. It's operated by Allegiant Air. The plane leaves Destin Fort Walton Beach Airport at 17:15 America/Chicago. The flight is expected to land at Will Rogers World Airport at 19:27 America/Chicago. The flight will last about 2 hours 3 minutes.

Frequently asked questions, answered

How long is the flight from Fort Walton Beach to Oklahoma City?

On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 1166 km (725 miles).

What type of aircraft is used for the Allegiant Air G41470 flight?

All Allegiant Air G41470 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G41470 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41470 is operated on Thursday.