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Allegiant Air G41448 Flight Status Today
Domestic flight Allegiant Air G41448 takes off from Akron (CAK) United States to Fort Walton Beach (VPS) United States. It's operated by Allegiant Air. The plane leaves Akron-Canton Airport at 16:13 13 April 2026 America/New_York. The flight is expected to land at Destin Fort Walton Beach Airport at 17:37 13 April 2026 America/Chicago. The flight will last about 2 hours 24 minutes.
Current status of G41448 is Scheduled On time Estimated Depart in 3 hours, 4 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 24 minutes
- Flight Distance: 1245 kms / 773 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Saturday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A319
- Callsign: F-KSGT1
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Akron: Monday 2026-04-13 13:09 PM
- Current Time in Fort Walton Beach: Monday 2026-04-13 12:09 PM
Allegiant Air Flight G41448 FAQs
What is the scheduled flight duration for Allegiant Air G41448 flight?
On average, nonstop flight takes 2 hour(s) 24 minutes, with the flight distance of 1245 km (773 miles).
What is the current status of Allegiant Air G41448 flight?
The current status of flight Allegiant Air G41448 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G41448 flight?
All Allegiant Air G41448 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41448 flights are operated a week?
3 flights per week. The Flight Allegiant Air G41448 is operated on Thursday, Saturday, Sunday.
