Allegiant Air G41439 Flight Status Today

Domestic flight Allegiant Air G41439 takes off from Knoxville (TYS) United States to Orlando (MCO) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 06:00 America/New_York. The flight is expected to land at Orlando International Airport at 07:34 America/New_York. The flight will last about 1 hours 30 minutes.

G41439 - AAY1439 Allegiant Air (G4)
TYS Knoxville United States
Flight TYS to MCO
MCO Orlando United States
Contact Airlines It may not operate on the date requested
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 06:00
None 2
Arrival Orlando International Airport
IATA: MCOICAO: KMCO
Scheduled 07:34
B 33
G41439 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 856 kms / 532 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KMCK1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Tuesday 2026-03-03 17:02 PM
  • Current Time in Orlando: Tuesday 2026-03-03 17:02 PM

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Allegiant Air Flight G41439 FAQs

What is the scheduled flight duration for Allegiant Air G41439 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 856 km (532 miles).

What type of aircraft is used for the Allegiant Air G41439 flight?

All Allegiant Air G41439 flights are operated using Airbus A320 (sharklets) aircraft.

Which terminal the flight Allegiant Air G41439 is arriving at?

Flight Allegiant Air G41439 arrives in Orlando International Airport at Terminal B.

How many Allegiant Air G41439 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41439 is operated on Thursday.