Allegiant Air G41429 Flight Status Today

Domestic flight Allegiant Air G41429 takes off from Orlando (SFB) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves Orlando Sanford International Airport at 15:17 America/New_York. The flight is expected to land at McGhee Tyson Airport at 16:56 America/New_York. The flight will last about 1 hours 39 minutes.

G41429 - AAY1429 Allegiant Air (G4)
SFB Orlando United States
Flight SFB to TYS
TYS Knoxville United States
Contact Airlines It may not operate on the date requested
Departure Orlando Sanford International Airport
IATA: SFBICAO: KSFB
Scheduled 15:17
None 4
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 16:56
None 4
G41429 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 39 minutes
  • Flight Distance: 821 kms / 510 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KHMN1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Orlando: Wednesday 2026-04-29 21:01 PM
  • Current Time in Knoxville: Wednesday 2026-04-29 21:01 PM

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Allegiant Air Flight G41429 FAQs

What is the scheduled flight duration for Allegiant Air G41429 flight?

On average, nonstop flight takes 1 hour(s) 39 minutes, with the flight distance of 821 km (510 miles).

What type of aircraft is used for the Allegiant Air G41429 flight?

All Allegiant Air G41429 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G41429 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41429 is operated on Monday.