Allegiant Air G41417 Flight Status Today

Domestic flight Allegiant Air G41417 takes off from Saint Petersburg (PIE) United States to Knoxville (TYS) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 16:59 America/New_York. The flight is expected to land at McGhee Tyson Airport at 18:37 America/New_York. The flight will last about 1 hours 38 minutes.

G41417 - AAY1417 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to TYS
TYS Knoxville United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 16:59
None 3
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 18:37
None None
G41417 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 38 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KSME1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Wednesday 2025-12-31 05:02 AM
  • Current Time in Knoxville: Wednesday 2025-12-31 05:02 AM

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Allegiant Air Flight G41417 FAQs

What is the scheduled flight duration for Allegiant Air G41417 flight?

On average, nonstop flight takes 1 hour(s) 38 minutes, with the flight distance of 884 km (549 miles).

What type of aircraft is used for the Allegiant Air G41417 flight?

All Allegiant Air G41417 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41417 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41417 is operated on Saturday.