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Allegiant Air G41413 Flight Status Today
Domestic flight Allegiant Air G41413 takes off from Knoxville (TYS) United States to Fort Walton Beach (VPS) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 07:00 03 May 2026 America/New_York. The flight is expected to land at Destin Fort Walton Beach Airport at 07:26 03 May 2026 America/Chicago. The flight will last about 1 hours 26 minutes.
Current status of G41413 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 1 hours 26 minutes
- Flight Distance: 635 kms / 395 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Friday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KMMI2
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Knoxville: Sunday 2026-05-03 09:55 AM
- Current Time in Fort Walton Beach: Sunday 2026-05-03 08:55 AM
Allegiant Air Flight G41413 FAQs
What is the scheduled flight duration for Allegiant Air G41413 flight?
On average, nonstop flight takes 1 hour(s) 26 minutes, with the flight distance of 635 km (395 miles).
What is the current status of Allegiant Air G41413 flight?
The current status of flight Allegiant Air G41413 is Arrived On time.
What type of aircraft is used for the Allegiant Air G41413 flight?
All Allegiant Air G41413 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G41413 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41413 is operated on Friday.
