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Allegiant Air G41399 Flight Status Today
Domestic flight Allegiant Air G41399 takes off from Middletown (MDT) United States to Jacksonville (JAX) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 16:04 America/New_York. The flight is expected to land at Jacksonville International Airport at 18:22 America/New_York. The flight will last about 2 hours 2 minutes.
- Type: Domestic Flight
- Flight Duration: 2 hours 2 minutes
- Flight Distance: 1166 kms / 724 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KTYS1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Middletown: Wednesday 2026-04-01 05:15 AM
- Current Time in Jacksonville: Wednesday 2026-04-01 05:15 AM
Flight routes similar to Allegiant Air G41399
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G43028 Allegiant Air |
01/04/2026 16:08 |
2 hours 18 minutes 18:26 |
Allegiant Air Flight G41399 FAQs
What is the scheduled flight duration for Allegiant Air G41399 flight?
On average, nonstop flight takes 2 hour(s) 2 minutes, with the flight distance of 1166 km (724 miles).
What type of aircraft is used for the Allegiant Air G41399 flight?
All Allegiant Air G41399 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G41399 flights are operated a week?
6 flights per week. The Flight Allegiant Air G41399 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.
