Allegiant Air G41098 Flight Status Today

Domestic flight Allegiant Air G41098 takes off from Niagara Falls (IAG) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Niagara Falls International Airport at 19:51 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 22:52 America/New_York. The flight will last about 3 hours 1 minutes.

G41098 - AAY1098 Allegiant Air (G4)
IAG Niagara Falls United States
Flight IAG to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Niagara Falls International Airport
IATA: IAGICAO: KIAG
Scheduled 19:51
None 3
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 22:52
None 8
G41098 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 1 minutes
  • Flight Distance: 1719 kms / 1068 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KTPA1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Niagara Falls: Sunday 2026-03-01 15:55 PM
  • Current Time in Saint Petersburg: Sunday 2026-03-01 15:55 PM

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Allegiant Air Flight G41098 FAQs

What is the scheduled flight duration for Allegiant Air G41098 flight?

On average, nonstop flight takes 3 hour(s) 1 minutes, with the flight distance of 1719 km (1068 miles).

What type of aircraft is used for the Allegiant Air G41098 flight?

All Allegiant Air G41098 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41098 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41098 is operated on Saturday.