Allegiant Air G41097 Flight Status Today

Domestic flight Allegiant Air G41097 takes off from Knoxville (TYS) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves McGhee Tyson Airport at 20:54 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 22:37 America/New_York. The flight will last about 1 hours 43 minutes.

G41097 - AAY1097 Allegiant Air (G4)
TYS Knoxville United States
Flight TYS to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 20:54
None 6
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 22:37
None 1
G41097 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 43 minutes
  • Flight Distance: 884 kms / 549 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KTRI3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Sunday 2026-03-22 08:46 AM
  • Current Time in Saint Petersburg: Sunday 2026-03-22 08:46 AM

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Allegiant Air Flight G41097 FAQs

What is the scheduled flight duration for Allegiant Air G41097 flight?

On average, nonstop flight takes 1 hour(s) 43 minutes, with the flight distance of 884 km (549 miles).

What type of aircraft is used for the Allegiant Air G41097 flight?

All Allegiant Air G41097 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G41097 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41097 is operated on Friday.