Allegiant Air G41093 Flight Status Today

Domestic flight Allegiant Air G41093 takes off from Greenville (GSP) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Greenville-Spartanburg International Airport at 15:09 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 16:39 America/New_York. The flight will last about 1 hours 30 minutes.

G41093 - AAY1093 Allegiant Air (G4)
GSP Greenville United States
Flight GSP to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Greenville-Spartanburg International Airport
IATA: GSPICAO: KGSP
Scheduled 15:09
None B1
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 16:39
None 4
G41093 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 775 kms / 482 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KBID1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Greenville: Sunday 2026-01-18 17:40 PM
  • Current Time in Saint Petersburg: Sunday 2026-01-18 17:40 PM

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Allegiant Air Flight G41093 FAQs

What is the scheduled flight duration for Allegiant Air G41093 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 775 km (482 miles).

What type of aircraft is used for the Allegiant Air G41093 flight?

All Allegiant Air G41093 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41093 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41093 is operated on Friday.