Allegiant Air G41085 Flight Status Today

Domestic flight Allegiant Air G41085 takes off from Louisville (SDF) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Louisville International Airport-Standiford Field at 10:57 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 13:04 America/New_York. The flight will last about 2 hours 7 minutes.

G41085 - AAY1085 Allegiant Air (G4)
SDF Louisville United States
Flight SDF to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Louisville International Airport-Standiford Field
IATA: SDFICAO: KSDF
Scheduled 10:57
None A10
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 13:04
None 5
G41085 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 7 minutes
  • Flight Distance: 1173 kms / 729 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KCTY2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Louisville: Monday 2026-03-02 15:23 PM
  • Current Time in Saint Petersburg: Monday 2026-03-02 15:23 PM

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Allegiant Air Flight G41085 FAQs

What is the scheduled flight duration for Allegiant Air G41085 flight?

On average, nonstop flight takes 2 hour(s) 7 minutes, with the flight distance of 1173 km (729 miles).

What type of aircraft is used for the Allegiant Air G41085 flight?

All Allegiant Air G41085 flights are operated using Airbus A320 aircraft.

How many Allegiant Air G41085 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41085 is operated on Sunday.