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Allegiant Air G41085 Flight Status Today
Domestic flight Allegiant Air G41085 takes off from Louisville (SDF) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Louisville International Airport-Standiford Field at 15:07 31 December 2025 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 16:49 31 December 2025 America/New_York. The flight will last about 2 hours 42 minutes.
Current status of G41085 is Scheduled On time Expected Depart in 6 hours, 48 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 42 minutes
- Flight Distance: 1173 kms / 729 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KCTY2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Louisville: Wednesday 2025-12-31 08:19 AM
- Current Time in Saint Petersburg: Wednesday 2025-12-31 08:19 AM
Allegiant Air Flight G41085 FAQs
What is the scheduled flight duration for Allegiant Air G41085 flight?
On average, nonstop flight takes 2 hour(s) 42 minutes, with the flight distance of 1173 km (729 miles).
What is the current status of Allegiant Air G41085 flight?
The current status of flight Allegiant Air G41085 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G41085 flight?
All Allegiant Air G41085 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41085 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41085 is operated on Sunday.
