Allegiant Air G41078 Flight Status Today

Domestic flight Allegiant Air G41078 takes off from Hagerstown (HGR) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Wash. County Regional Airport at 18:27 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 20:49 America/New_York. The flight will last about 2 hours 22 minutes.

G41078 - AAY1078 Allegiant Air (G4)
HGR Hagerstown United States
Flight HGR to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Wash. County Regional Airport
IATA: HGRICAO: KHGR
Scheduled 18:27
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 20:49
None None
G41078 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 22 minutes
  • Flight Distance: 1386 kms / 861 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Friday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KATL3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Hagerstown: Monday 2025-12-29 21:57 PM
  • Current Time in Saint Petersburg: Monday 2025-12-29 21:57 PM

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Allegiant Air Flight G41078 FAQs

What is the scheduled flight duration for Allegiant Air G41078 flight?

On average, nonstop flight takes 2 hour(s) 22 minutes, with the flight distance of 1386 km (861 miles).

What type of aircraft is used for the Allegiant Air G41078 flight?

All Allegiant Air G41078 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41078 flights are operated a week?

3 flights per week. The Flight Allegiant Air G41078 is operated on Monday, Friday, Saturday.