Check your Flight status online
Allegiant Air G41073 Flight Status Today
Domestic flight Allegiant Air G41073 takes off from Memphis (MEM) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Memphis International Airport at 08:22 America/Chicago. The flight is expected to land at St. Petersburg-Clearwater International Airport at 11:06 America/New_York. The flight will last about 1 hours 44 minutes.
G41073 - AAY1073
Allegiant Air (G4)
MEM
Memphis United States
PIE
Saint Petersburg United States
Contact Airlines
It may not operate on the date requested
G41073 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 44 minutes
- Flight Distance: 1050 kms / 653 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KTPA1
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Memphis: Monday 2026-01-19 01:35 AM
- Current Time in Saint Petersburg: Monday 2026-01-19 02:35 AM
Allegiant Air Flight G41073 FAQs
What is the scheduled flight duration for Allegiant Air G41073 flight?
On average, nonstop flight takes 1 hour(s) 44 minutes, with the flight distance of 1050 km (653 miles).
What type of aircraft is used for the Allegiant Air G41073 flight?
All Allegiant Air G41073 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41073 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41073 is operated on Thursday.
