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Allegiant Air G41069 Flight Status Today
Domestic flight Allegiant Air G41069 takes off from Memphis (MEM) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Memphis International Airport at 20:25 America/Chicago. The flight is expected to land at St. Petersburg-Clearwater International Airport at 23:14 America/New_York. The flight will last about 1 hours 49 minutes.
G41069 - AAY1069
Allegiant Air (G4)
MEM
Memphis United States
PIE
Saint Petersburg United States
Contact Airlines
It may not operate on the date requested
G41069 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 49 minutes
- Flight Distance: 1050 kms / 653 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Sunday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KVDF2
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Memphis: Sunday 2026-01-18 16:32 PM
- Current Time in Saint Petersburg: Sunday 2026-01-18 17:32 PM
Allegiant Air Flight G41069 FAQs
What is the scheduled flight duration for Allegiant Air G41069 flight?
On average, nonstop flight takes 1 hour(s) 49 minutes, with the flight distance of 1050 km (653 miles).
What type of aircraft is used for the Allegiant Air G41069 flight?
All Allegiant Air G41069 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41069 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41069 is operated on Sunday.
