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Allegiant Air G41041 Flight Status Today
Domestic flight Allegiant Air G41041 takes off from Saint Petersburg (PIE) United States to Omaha (OMA) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 07:00 America/New_York. The flight is expected to land at Eppley Airfield at 09:17 America/Chicago. The flight will last about 3 hours 17 minutes.
G41041 - AAY1041
Allegiant Air (G4)
PIE
Saint Petersburg United States
OMA
Omaha United States
Contact Airlines
It may not operate on the date requested
Scheduled
07:00
None
3
G41041 Detail
- Type: Domestic Flight
- Flight Duration: 3 hours 17 minutes
- Flight Distance: 1912 kms / 1188 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Wednesday, Friday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KALX1
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Monday 2026-03-23 19:15 PM
- Current Time in Omaha: Monday 2026-03-23 18:15 PM
Allegiant Air Flight G41041 FAQs
What is the scheduled flight duration for Allegiant Air G41041 flight?
On average, nonstop flight takes 3 hour(s) 17 minutes, with the flight distance of 1912 km (1188 miles).
What type of aircraft is used for the Allegiant Air G41041 flight?
All Allegiant Air G41041 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41041 flights are operated a week?
3 flights per week. The Flight Allegiant Air G41041 is operated on Monday, Wednesday, Friday.
