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Allegiant Air G41041 Flight Status Today
Domestic flight Allegiant Air G41041 takes off from Saint Petersburg (PIE) United States to Omaha (OMA) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 07:00 02 March 2026 America/New_York. The flight is expected to land at Eppley Airfield at 09:17 02 March 2026 America/Chicago. The flight will last about 3 hours 17 minutes.
Current status of G41041 is Departed On time Estimated Arrival in 1 hour, 5 minutes
- Type: Domestic Flight
- Flight Duration: 3 hours 17 minutes
- Flight Distance: 1912 kms / 1188 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Wednesday, Friday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KALX1
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Monday 2026-03-02 08:38 AM
- Current Time in Omaha: Monday 2026-03-02 07:38 AM
Allegiant Air Flight G41041 FAQs
What is the scheduled flight duration for Allegiant Air G41041 flight?
On average, nonstop flight takes 3 hour(s) 17 minutes, with the flight distance of 1912 km (1188 miles).
What is the current status of Allegiant Air G41041 flight?
The current status of flight Allegiant Air G41041 is Departed On time.
What type of aircraft is used for the Allegiant Air G41041 flight?
All Allegiant Air G41041 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41041 flights are operated a week?
3 flights per week. The Flight Allegiant Air G41041 is operated on Monday, Wednesday, Friday.
