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Allegiant Air G41038 Flight Status Today
Domestic flight Allegiant Air G41038 takes off from Saint Petersburg (PIE) United States to Memphis (MEM) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 18:09 18 January 2026 America/New_York. The flight is expected to land at Memphis International Airport at 20:13 18 January 2026 America/Chicago. The flight will last about 2 hours 4 minutes.
Current status of G41038 is Scheduled On time Expected Depart in 6 hours
G41038 - AAY1038
Allegiant Air (G4)
PIE
Saint Petersburg United States
MEM
Memphis United States
Scheduled On time
Expected Depart in 6 hours
Scheduled
18:09 18 January 2026
None
B3
G41038 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 4 minutes
- Flight Distance: 1050 kms / 653 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Saturday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KJQF1
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Sunday 2026-01-18 12:09 PM
- Current Time in Memphis: Sunday 2026-01-18 11:09 AM
Flight routes similar to Allegiant Air G41038
Allegiant Air Flight G41038 FAQs
What is the scheduled flight duration for Allegiant Air G41038 flight?
On average, nonstop flight takes 2 hour(s) 4 minutes, with the flight distance of 1050 km (653 miles).
What is the current status of Allegiant Air G41038 flight?
The current status of flight Allegiant Air G41038 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G41038 flight?
All Allegiant Air G41038 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G41038 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41038 is operated on Saturday.