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Allegiant Air G41033 Flight Status Today
Domestic flight Allegiant Air G41033 takes off from Saint Petersburg (PIE) United States to Greenville (GSP) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 13:23 America/New_York. The flight is expected to land at Greenville-Spartanburg International Airport at 14:50 America/New_York. The flight will last about 1 hours 34 minutes.
G41033 - AAY1033
Allegiant Air (G4)
PIE
Saint Petersburg United States
GSP
Greenville United States
Contact Airlines
It may not operate on the date requested
Scheduled
13:23
None
10
G41033 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 34 minutes
- Flight Distance: 775 kms / 482 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Friday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A319
- Callsign: F-KHSV4
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Monday 2026-01-19 05:11 AM
- Current Time in Greenville: Monday 2026-01-19 05:11 AM
Allegiant Air Flight G41033 FAQs
What is the scheduled flight duration for Allegiant Air G41033 flight?
On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 775 km (482 miles).
What type of aircraft is used for the Allegiant Air G41033 flight?
All Allegiant Air G41033 flights are operated using Airbus A319 aircraft.
How many Allegiant Air G41033 flights are operated a week?
1 flights per week. The Flight Allegiant Air G41033 is operated on Friday.
