Allegiant Air G41028 Flight Status Today

Domestic flight Allegiant Air G41028 takes off from Saint Petersburg (PIE) United States to Roanoke (ROA) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 13:15 America/New_York. The flight is expected to land at Roanoke-Blacksburg Regional Airport at 15:11 America/New_York. The flight will last about 2 hours 9 minutes.

G41028 - AAY1028 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to ROA
ROA Roanoke United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 13:15
None 7
Arrival Roanoke-Blacksburg Regional Airport
IATA: ROAICAO: KROA
Scheduled 15:11
None 6
G41028 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 9 minutes
  • Flight Distance: 1074 kms / 667 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KBKT1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-01-19 23:15 PM
  • Current Time in Roanoke: Monday 2026-01-19 23:15 PM

Allegiant Air Flight G41028 FAQs

What is the scheduled flight duration for Allegiant Air G41028 flight?

On average, nonstop flight takes 2 hour(s) 9 minutes, with the flight distance of 1074 km (667 miles).

What type of aircraft is used for the Allegiant Air G41028 flight?

All Allegiant Air G41028 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41028 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41028 is operated on Thursday.